20261027
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79
Question2/MySQL SQL問題集 part2.sql
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79
Question2/MySQL SQL問題集 part2.sql
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--<EFBFBD><EFBFBD><EFBFBD>P
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CREATE TABLE item_category (
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category_id INT AUTO_INCREMENT PRIMARY KEY,
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category_name VARCHAR(256) NOT NULL
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);
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INSERT INTO item_category(category_name) VALUES('<EFBFBD>Ƌ<EFBFBD>'),('<EFBFBD><EFBFBD><EFBFBD><EFBFBD>'),('<EFBFBD>H<EFBFBD>i');
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--<EFBFBD><EFBFBD><EFBFBD>Q
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CREATE TABLE items(
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item_id INT AUTO_INCREMENT PRIMARY KEY,
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name VARCHAR(256) NOT NULL,
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price INT NOT NULL,
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category_id INT,
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FOREIGN KEY(category_id) REFERENCES item_category(category_id)
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);
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INSERT INTO items(name,price,category_id)
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VALUES('<EFBFBD><EFBFBD><EFBFBD>[<5B>}<7D>̃e<CC83>[<5B>u<EFBFBD><75>',150000,1),('<EFBFBD><EFBFBD><EFBFBD>[<5B><><EFBFBD><EFBFBD><EFBFBD>[<5B><>2000 500ml',370,2),('<EFBFBD><EFBFBD><EFBFBD>n<EFBFBD><EFBFBD>',2500,3),('<EFBFBD><EFBFBD><EFBFBD>f<EFBFBD>̈֎q',100000,1);
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--<EFBFBD><EFBFBD><EFBFBD>R
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SELECT
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a.item_id,
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a.name,
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a.price,
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b.category_id,
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b.category_name
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FROM items a
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INNER JOIN item_category b
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ON a.category_id = b.category_id;
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--<EFBFBD><EFBFBD><EFBFBD>S
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SELECT *
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FROM items
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ORDER BY price;
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--<EFBFBD><EFBFBD><EFBFBD>T
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SELECT
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a.item_id,
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a.name,
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a.price,
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b.category_id,
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b.category_name
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FROM items a
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INNER JOIN item_category b
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ON a.category_id = b.category_id AND b.category_name = '<EFBFBD>Ƌ<EFBFBD>';
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--<EFBFBD><EFBFBD><EFBFBD>U
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SELECT
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a.item_id,
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a.name,
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a.price,
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b.category_id,
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b.category_name
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FROM items a
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INNER JOIN item_category b
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ON a.category_id = b.category_id AND a.price <= 50000 AND a.price >= 1000;
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--<EFBFBD><EFBFBD><EFBFBD>V
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SELECT COUNT(*) AS data_count
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FROM items;
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--<EFBFBD><EFBFBD><EFBFBD>W
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SELECT * FROM items
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WHERE price = (SELECT MAX(price) FROM items);
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--<EFBFBD><EFBFBD><EFBFBD>X
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SELECT
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a.item_id,
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a.name,
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a.price,
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b.category_id,
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b.category_name
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FROM items a
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INNER JOIN item_category b
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ON a.category_id = b.category_id
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WHERE a.name LIKE'%<25><>%';
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