MySQL SQL練習問題20261027

MYSQL_Question2_5-.txt

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+--問5
+select * from items inner join item_category using(category_id) where category_name = '家具';
+
+--問6
+select * from items inner join item_category using(category_id) where price between 1000 and 50000;
+
+--問7
+select count(*) as data_count from items;
+
+--問8
+select * from items inner join item_category using(category_id) where  price = (select max(price) from items);
+
+--問9
+select * from items inner join item_category using(category_id) where name like '%の%';

Question2+α.txt

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+--問1
+select items.item_id as 商品ID, items.name as 商品名, items.price as 価格, 
+    item_category.name as カテゴリ名 from items inner join item_category using(category_id);
+    
+--問2
+select orders.order_id as 注文ID, orders.order_time as 注文日時, users.name as ユーザー名, 
+    items.name as 商品名, items.price as 価格, order_items.quantity as 数量 from order_items
+    inner join orders using(order_id)
+    inner join items using(item_id)
+    inner join users using(user_id) order by orders.order_time;